Question 945226
These are sum and differences of cubes which can be factored using these formulas,
{{{u^3+v^3=(u+v)(u^2-uv+v^2)}}}
{{{u^3-v^3=(u-v)(u^2+uv+v^2)}}}
So just substitute into the appropriate formula.
I'll do one.
You do the rest.
{{{8x^3-27=0}}}
{{{u=2x}}}
{{{v=3}}}
{{{8x^3-27=0}}}
{{{(2x-3)(4x^2+6x+9)=0}}}