Question 10914
{{{-(x+1) = 2(3x-1)}}}
{{{-x-1 = 2(3x-1)}}} ... distribute the negative sign on the left
{{{-x-1 = 6x-2}}} ... distribute the 2 on the right
{{{-1 = 7x-2}}} ... add x to both sides
{{{1 = 7x}}} ... add 2 to both sides
{{{1/7 = x}}} ... divide both sides by 7


Thus, x = 1/7.  To check, we substitute 1/7 in for x in the original equality, and see if it holds true.

{{{-(1/7+1) = 2(3(1/7)-1)}}}
{{{-(1/7+7/7) = 2(3(1/7)-1)}}}
{{{-8/7 = 2(3(1/7)-1)}}}
{{{-8/7 = 2(3/7-1)}}}
{{{-8/7 = 2(3/7-7/7)}}}
{{{-8/7 = 2(-4/7)}}}
{{{-8/7 = -8/7}}} ... yes!