Question 945129
The walkway has area 216 sq ft the pool has area (15 ft)(15 ft)=225 sq ft
Together a total area of (216 sq ft+225 sq ft)=441 sq ft since The pool and path form a square (the pool is 15ft x 15 ft  and the path uniform around it)
The sides (s) of the total area are 
{{{s^2=441 sq ft}}}
{{{s=sqrt(441 sq ft)}}}={{{21 feet}}}
Each side of the total area spans the width of the path on one side then the width of the pool then the path on the other side so:
Total side=width of path + width of pool + width of path= 2*width of path+width of pool 
width of path=(Total width-width of pool)/2
width of path=(21 feet - 15 feet)/2= 6 feet/2=3 Feet 
ANSWER the width of the path is 3 feet