Question 945074
x, both for the side length of square and diameter of circle.


{{{4x-2pi*r}}}, using r for radius, and know that {{{2r=x}}}, so {{{r=x/2}}}.
{{{4x-2pi(x/2)}}}
{{{4x-2(x/2)pi}}}
{{{highlight(4x-pi*x)}}}