Question 945054
the sum of three consecutive numbers is 56. the second is five less than the first and the third is 15 more than the smallest. find the three numbers.
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let x=first number
x-5=second number (this must be the smallest of the 3 numbers)
x-5+15=x+10=third number
x+x-5+x+10=56
3x=51
x=17
x-5=12
x+10=27
..
first number=17
second number=12
third number=27