<PRE><B>Question 945050</B>
Difficult to understand through viewing the two expressions.  COMPLETE The SQUARE to transform the left member into standard form, and then you can identify k by corresponding position.


See your lesson on completing the square so you know why the term to use for this will be {{{(5/2)^2=25/4}}}.


{{{x^2-5x+(5/2)^2+6-(5/2)^2}}}
{{{(x-5/2)^2+6-25/4}}}
{{{(x-5/2)^2+24/4-25/4}}}
{{{(x-5/2)^2-1/4=(x-h)^2+k}}}



{{{highlight(k=-1/4)}}}</PRE>