Question 944797
let a = the 100's digit
let b = the 10's digit
let c = the units
then
100a+10b+c = the number
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Write an equation for each statement: 

twice the hundreds digit is the tens digit.
2a = b
 the unit digit is four more than the hundreds digit.
c = a + 4
 the sum of the number and the number formed by reversing the digits is 888.
(100a + 10b + c) + (100c + 10b + a) = 888
combine like terms
100a + a + 10b + 10b + 100c + c = 888
101a + 20b + 101c = 888
replace b with 2a; replace c with (a+4)
101a + 20(2a) + 101(a+4) = 888
101a + 40a + 101a + 404 = 888
242a = 888 - 404
242a = 484
a = 484/242
a = 2
then
b = 2(2) = 4
and
c = 2 + 4 = 6
 what is the number: 246 is the number
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Check this 246  + 642 = 888
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