Question 944959

Two angles  {{{alpha}}} and {{{beta}}} are supplementary and it means they add up to {{{180}}}°.

so, {{{alpha+beta=180}}} .........eq.1

if the measure of one angle (let’s say {{{alpha}}}) is {{{5}}} greater than {{{40}}}% of the other {{{beta}}}, then we have

 {{{alpha=(40/100)beta+5}}}....eq.2 .......substitute in eq.1

{{{(40/100)beta+5+beta=180}}} ....solve for {{{beta}}}

{{{0.40beta+beta=180-5}}}

{{{1.40beta=175}}}

{{{beta=175/1.40}}}

{{{highlight(beta=125)}}}°

then  {{{alpha+125=180}}} =>{{{alpha=180-125}}} =>{{{highlight(alpha=55)}}}°