Question 944880

{{{(x+6)/(6-x) < 0}}}

denominator cannot be zero; so, {{{(6-x)}}} will be {{{ 0}}} if {{{x=6}}}

it means {{{x}}} must be greater then {{{6}}}

{{{highlight(x > 6)}}} 

the values of {{{x}}} are:{ {{{7}}},{{{8}}},{{{9}}},......}

and these values make the inequality {{{(x+6)/(6-x) < 0}}} true



try for {{{x=7}}}

{{{(7+6)/(6-7) < 0}}}

{{{13/-1 < 0}}}

{{{-13<0}}} which is true