Question 944772
The shortest path to the start is the hypotenuse of the right triangle so since
{{{A^2+B^2=C^2}}}
{{{C=sqrt(A^2+B^2)}}}
{{{C=sqrt(119^2+120^2)}}}
{{{C=sqrt(14161+14400)}}}
{{{C=sqrt(28561)}}}
C=169 ANSWER The shortest distance between the start and end points is 169 feet.