Question 944822
{{{graph(300,300,-2,8,-5,5,x^3 - 16x^2 + 85x - 148)}}}
Looks like {{{highlight(x=4)}}} is a zero. 
Verifying,
{{{64-16*16+85*4-148=0}}}
{{{64-256+340-148=0}}}
{{{0=0}}}
.
.
So then,
{{{(x^3 - 16x^2 + 85x - 148)/(x-4)=x^2-12x+37}}}
So,
{{{x^2-12x+37=0}}}
{{{x^2-12x+36+1=0}}}
{{{(x-6)^2=-1}}}
{{{x-6=0 +- sqrt(-1)}}}
{{{highlight(x= 6 +- i)}}}