Question 944868

{{{(x+y)^2}}} is square of the sum and it is equal to {{{x^2+2⁢xy+y^2}}} and it is a perfect square trinomial

and {{{x^2+y^2}}} is the sum of the squares

why {{{(x+y)^2}}} is not equal to {{{x^2+y^2}}}, : because it is a binomial and {{{(x+y)^2}}} is {{{2⁢xy}}} greater then {{{x^2+y^2}}}