Question 944828
-40 = 100t + 1/2 (-9.8)t^2
-4.9t^2 +100t +40 = 0
this is an equation of a parabola that opens downward
max height in meters is determined by solving for the axis of symmetry
t = -b/2a = -100 / (2*-4.9) = 10.204081633, therefore
max height occurs at 10.204081633 seconds and max height is
h(t) = -4.9(10.204081633^2) +100*(10.204081633) +40
max height = 550.204081633 meters