Question 944813
A graph shows the equation {{{y=4sqrt(x)}}}
a.how many real roots does {{{4sqrt(16)}}} have?

if {{{y=4sqrt(16)}}}=>{{{y=4*4}}} =>{{{y=16}}} and that is ONE real root

b.how many real roots does {{{4sqrt(-16)}}} have? 
answer is NONE, the square root of a negative number does not exist among the set of Real Numbers 

{{{y=4sqrt(-16)}}}=>{{{y=4*(4i)}}} or {{{y=4*(-4i)}}} =>{{{y=16i}}} or {{{y=-16i}}}


 the principal root of {{{root(3,-125)}}} is {{{-5}}} because {{{(-5)^3 = -125}}}