Question 944795

{{{2x-y= -10}}}.....eq.1....both sides multiply by {{{2}}}
{{{4x-2y= -2}}}.....eq.2
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{{{4x-2y= -20}}}.....eq.1
{{{4x-2y= -2}}}.....eq.2
-----------------------------------subtract eq.2 from eq.1

{{{4x-2y-(4x-2y)= -20-(-2)}}}

{{{4x-2y-4x+2y= -20+2}}}

{{{cross(4x)-cross(2y)-cross(4x)+cross(2y)= -18}}}

{{{0= -18}}} which is not true; so, it means that the two lines are {{{parallel}}} and will never intersect,there are no solutions and the system is {{{inconsistent}}}


 {{{ graph( 600, 600, -10, 10, -10, 15, 2x+10,2x+1) }}}