Question 944780
Consider the expression, {{{ r^s = A(t-p)^x }}} . An equivalent logarithmic expression is. r is the base
base = r
exponent = log = s
result = A(t-p)^x
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Answer: s = logr[A(t-p)^x]
Cheers,
Stan H.
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A. {{{ s = A log ( r, (t-p))^x }}} 
B. {{{ s = log ( r, Ax (t-p)) }}}
C. {{{ s = Ax log ( r, (t-p)) }}}
D. {{{ s = log ( r, A)(t-p)^x }}}