Question 944492
{{{P=P[o]e^(rt)}}}


{{{2=1*e^(rt)}}}


{{{e^(rt)=2}}}


{{{ln(e^(rt))=ln(2)}}}


{{{rt*1=ln(2)}}}


{{{t=(1/r)(ln(2))}}}


2% means 0.02.


{{{t=(1/0.02)ln(2)}}}


{{{highlight(t=35)}}}   years.