Question 944518
Simplify: 

{{{((2x^-1)+(3x^-1))/((9x^2)-(4y^2))}}}....first write {{{x^-1}}} as {{{1/x}}}, {{{(9x^2)}}} as {{{(3x)^2}}}, and {{{4y^2}}} as {{{(2y)^2}}}


{{{(2(1/x)+3(1/x))/((3x)^2-((2y)^2))}}}


{{{(2/x+3/x)/((3x-2y)(3x+2y))}}}


{{{(5/x)/((3x-2y)(3x+2y))}}}


{{{5/(x(3x-2y)(3x+2y))}}}