Question 944389
Hi Grace, here is how to do this problem:

{{{(6x+7)/(4x-1) = (3x+8)/(2x-4 )}}}..cross multiply

{{{(6x+7)(2x-4 ) = (3x+8)(4x-1)}}}

{{{6x*2x-4*6x+7*2x-4*7 = 3x*4x-3x*1+8*4x-1*8}}}

{{{cross(12x^2)-24x+14x-28 = cross(12x^2)-3x+32x-8}}}

{{{-10x-28 = 29x-8}}}

{{{8-28 = 29x+10x}}}

{{{-20 = 39x}}}

{{{-20/39=x}}}