Question 944267
x = speed of slow car (kph)
y = speed of fast car (kph)
y = x + 14
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s = d/t
t = d/s
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speed of cars relative to each other:
s = x + y
s = x + x + 14
s = 2x + 14
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s = 600/3
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equate s's:
2x + 14 = 600/3
2x = 600/3 - 14
x = (600/3 - 14)/2
(600/3 - 14)/2
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x = 93
y = x + 14
y = 93 + 14
y = 107
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answer:
y = speed of fast car (kph) = 107
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