Question 80151
{{{sin2x+(1/2)=0}}}
Get the the x term alone on one side of the equation:
{{{sin2x=-1/2}}}
Take the inverse sin of both sides:
{{{arcsin(sin2x)=arcsin(-1/2)}}}
Solve for x:
{{{2x=-30}}} and {{{2x=210}}} (recall that sin is negative in Quadrants 3+4)
{{{x=-15 degrees}}} and {{{x=105 degrees}}}
Good Luck,
tutor_paul@yahoo.com