Question 944049
{{{root(3,v^3)=v}}};

for {{{n>0}}} and {{{n<3}}}, {{{root(3,v^(3+n))=v*root(3,v^n)}}}.



Showing the intermediate step may be helpful:
{{{root(3,x^19*y^6*z)=root(3,x^18*x*y^3*y^3*z)=root(3,(x^3)^6*x*y^3*y^3*z)}}}
{{{root(3,x*x^3*x^3*x^3*x^3*x^3*x^3*y^3*y^3*z)}}}