Question 944015
Express the following in index form
 Logx + logy =1
log(xy) = 1
xy = 10
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 Logx =6
x = 10^6 = 1000000
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 Log (x+4) = log64
log(x+4)/(64) = 0
(x+4)/64 = 1
x+4 = 64
x = 60
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 Log (2x+1) - log (3x-2)
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= log[(2x+1)/(3x-2)]
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 Log (3x-1) - log2 = 3
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log[(3x-1)/2] = 3
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(3x-1)/2 = 10^3
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3x-1 = 2000
3x = 2001
x = 667
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cheers,
Stan H.
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