Question 944001
The two definitions for h(x) are not equal to each-other; do you WANT them to be set as equal, and then to solve for x?  Also, the second definition is ambiguous, so helping with it is less reliable.  What is it?  {{{-sqrt(x-1)}}}?  {{{-sqrt(x)-1}}}?  {{{-(sqrt(x)-1)}}}?


(Some discussion given privately)
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Here is what your second function looks like when surrounded by the triple braces rendering tags:
{{{h(x)=-sqrt x-1}}}
which is just as ambiguous as without the rendering tags.
WHAT FUNCTION DO YOU REALLY HAVE FOR THIS?