Question 943725
x^2 - 3xy + 2y^2 = 0
we want to factor this, the factors of 2, are 1 and 2, so we have
(x - 1y )(x - 2y) = 0
perhaps it will help if you're familiar with "FOIL," if you FOIL these two factors:
x^2 - 2xy - xy + 2y^2
combine like terms
x^2 - 3xy + 2y^2 = 0, the original quadratic equation
:
I don't know how you get 40 out of this. ankor@att.net if you have a question