Question 943743
Consider the expression y = rlog(n) (x+p)^w. An equivalent exponential
expression is:
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1st:: Apply the Rule:: alog(n)(x) = log(n)x^a to get:
y = log(n)[(x+p)^w]^r
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base:: n
log = exponent = y
result = (x+p)^w^r
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Write in exponential form::
n^y = (x+p)^w^r
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Cheers,
Stan H.
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 a. n^y = r(x+p)^w
 b. n^y = (x+p)^w^r
 c. n^y = (x+p)^w-r
 d. n^y = (x+p)^w+r