Question 943681
 cubic foot of water weighs 62.4 lb.
 A basketball has a radius of 0.39 ft.
 How much would the basketball weigh if it was filled with water (to the nearest tenth)?
:
Find the volume of the ball; V = {{{4/3}}}*{{{pi*r^3}}}, where r = .39 ft
V = {{{4/3}}}*{{{pi*.39^3}}}
enter this in your calculator, you should get:
V = .248475 cu/ft
Find weight of this much water in the ball
.248475 * 62.4 = 15.5 lb, weight of the ball filled with water.