<PRE><B>Question 80193</B>
n-5 1 n-3
---- = --- - ----
6n-6 9 4n-4 
:
Assume you mean:
:
{{{((n-5)/(6n-6))}}} = {{{1/9}}} - {{{((n-3)/(4n-4))}}}
:
Factor out what you can in the denominator
:
{{{((n-5)/(6(n-1)))}}} = {{{1/9}}} - {{{((n-3)/(4(n-1)))}}}
:
6, 4, 9 are all factors of 36, our common denominator is 36(n-1)
Multiplying each term will get rid of the denominator, we then have:
:
6(n-5) = 4(n-1) - 9(n-3)
:
6n - 30 = (4n - 4) - (9n - 27)
:
6n - 30 = 4n - 4 - 9n + 27
:
6n -30 = -5n + 23
:
6n + 5n = 23 + 30
:
11n = 53
:
n = 53/11
:
n ~ 4.8, I used this to check for equality and it checked out </PRE>