Question 943360
A $6000 investment at an annual simple interest rate of 3.6% earned as much interest after one year as another investment in an account that earned 4.5% annual simple interest. How much was invested at 4.5%?

Solution:
Let x = amount invested at 4.5%
0.045x = 0.036(6000)
Divide both sides by 0.045
x = 0.036(6000)/0.045
Therefore, x = $4800  [Answer]