Question 943147
Although this problem is set up to solve by substitution, here is the elimination method.
Multiply the second equation by {{{-2}}} and add to the first.
{{{2x+3y-2x=8-4y+6}}}
{{{3y=14-4y}}}
{{{7y=14}}}
{{{y=2}}}
Then,
{{{x=2(2)-3}}}
{{{x=4-3}}}
{{{x=1}}}