<PRE><B>Question 80161</B>
With 300 turns, the tire of a car advanced 584 m. Assuming that there was no slipping, what is the diameter of that wheel to the nearest hundredth of a meter?
:
Find the circumference:
C = 584/300
:
C = 1.9467 meters
:
Find the diameter by by substituting in the Circumference equation;C = pi*diameter
:
pi*d = 1.9467
:
d = {{{1.9467/pi}}}
:
d = .62 meters
:
Check solution: pi*.62*300 = 584.33 ~ 584 
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