Question 942916
{{{y=ab^x}}}
{{{24=ab^(-3)}}}
{{{a/b^3=24}}}
1.{{{a=24b^3}}}
.
.
{{{12=ab^(-2)}}}
{{{a/b^2=12}}}
2.{{{a=12b^2}}}
Equate eq. 1 by eq. 2,
{{{24b^3=12b^2}}}
{{{2b=1}}}
{{{b=1/2}}}
Then,
{{{a=12(1/2)^2}}}
{{{a=12(1/4)}}}
{{{a=3}}}
So then,
{{{highlight(y=3/(2)^(x))}}}