Question 942849
Perpendicular Bisector of AB.


Slope for AB is {{{(2-(-3))/(3-2)=5}}}.  The line perpendicular to AB must have slope {{{-1/5}}}.


Midpoint of AB is
{{{x=(3+2)/2=5/2}}}
and 
{{{y=(2+(-3))/2=-1/2}}}.
As ordered pair of coordinates, this midpoint is (5/2,-1/2).


The line for any point P will be  {{{highlight_green(y-(-1/2)=(-1/5)(x-5/2))}}} using POINT-SLOPE form for equation of a line.  Simplify and put into whatever form you want.