Question 942761
Expanding each term,
{{{cos(x+pi/6)=(sqrt(3)/2)cos(x)-sin(x)/2}}}
{{{sin(x-pi/3)=sin(x)/2-(sqrt(3/2))cos(x)}}}
Then adding them together,

{{{cos(x+pi/6)+sin(x-pi/3)=(sqrt(3)/2)cos(x)-sin(x)/2+sin(x)/2-(sqrt(3/2))cos(x)}}}
{{{cos(x+pi/6)+sin(x-pi/3)=0}}}