Question 942795
Divide the successive term by the previous term,
{{{243/81=3}}}
{{{81/27=3}}}
So each term is divided by {{{3}}} or multiplied by {{{(1/3)}}},
{{{a[n]=243*(1/3)^(n-1)}}}
{{{a[n]=243*(1/3)^n*(1/3)^(-1)}}}
{{{a[n]=243*(1/3)^n*3}}}
{{{a[n]=729*(1/3)^n}}}