Question 942660
what does x equal in this

square root of x plus six equals to zero

the six is not in the square root symbol
Please show the work as to how you got it
<pre>
{{{sqrt(x) + 6 = 0}}}
{{{sqrt(x) = - 6}}} -------- Subtracting 6
{{{(sqrt(x))^2 = (- 6)^2}}} --- Squaring both sides
x = 36, but when checked, it happens to be an EXTRANEOUS solution, so there's NO SOLUTION to this equation.