Question 942691

{{{y=-(1/2)x-4}}}...here you have a linear equation, graph is a line

if you compare it to the slope-intercept form {{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept, we see that {{{m=-(1/2)}}} and {{{b=-4}}}

to graph these line we already have one point and it is y-intercept ({{{0}}},{{{-4}}}), so we need one more point to draw a graph

easiest is to find x-intercept, so set {{{y=0}}} and solve for {{{x}}}

{{{0=-(1/2)x-4}}}

{{{4=-(1/2)x}}}

{{{4*2=-2(1/2)x}}}

{{{8=-x}}}

{{{x=-8}}}

x-intercept is at ({{{-8}}},{{{0}}})

now plot these points and draw a line through:

{{{ graph( 600, 600, -15, 15, -15, 15, -(1/2)x-4) }}}