Question 942592
first=x, second =x+1, third=x+2, fourth=x+3, fifth=x+4
3x+56=x+3+x+4
3x+56=2x+7 subtract 2x from each side
3x-2x+56=2x+7-2x
x+56=7 subtract 56 from each side
x+56-56=7-56
x=-49 first= -49
fourth=x+3=-46
fifth=x+4=-45
CHECK: Sum offourth and fifth is 56 more than triple first
-45+-46=3(-49)+56
-91=(-147)+56
-91=-91