Question 942550
x-intercepts:
y = 0
(x-2)^2 - (y-1)^2 = 9
(x-2)^2 - (0-1)^2 = 9
(x-2)^2 - (-1)*(-1) = 9
xx - 4x + 4 = 9 + 1
xx - 4x - 6 = 0
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the above quadratic equation is in standard form, with a=1, b=-4 and c=-6
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
1 -4 -6
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has two real roots (the x-intercepts), located at:
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x = 5.16227766
x = -1.16227766
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y-intercepts:
x = 0
(x-2)^2 - (y-1)^2 = 9
(0-2)^2 - (y-1)^2 = 9
(-2)*(-2) - (y-1)^2 = 9
-(y-1)^2 = 9 - 4
-(yy - 2y + 1) = 5
-yy + 2y - 1 = 5
-yy + 2y - 6 = 0
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the above quadratic equation is in standard form, with a=-1, b=2 and c=-6
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
-1 2 -6
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has two complex roots, located at:
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y = 1 + (-2.23606798)i
y = 1 - (-2.23606798)i
complex roots are not on the y-axis, therefore this hyperbola does not have y-intercepts
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