Question 942178
Interchange x and y.
{{{x=2(y-2)^2-3}}}
Now solve for y, that'll be the inverse.
{{{x+3=2(y-2)^2}}}
{{{(y-2)^2=(x+3)/2}}}
{{{y-2=0 +- sqrt((x+3)/2)}}}
{{{y= 2 +- sqrt((x+3)/2)}}}
Original is a function.
Inverse is not (multiple y values for one x value)