Question 942140
I= first integer, I+2=second I+4=third
I+(I+2)+(I+4)=93
3I+6=93 subtract 6 from each side
3I+6-6=93-6
3I=87 divide both sides by 3
3I/3=87/3
I=29 ANSWER first integer=29
I+2=31 ANSWER second integer=31
I+4=33 ANSWER third integer=33
Check:
sum of three consecutive odd integers=93
29+31+33=93
93=93