Question 941857
10.) find the slope of the line that passes thru ({{{6}}},{{{-2}}}) and ({{{-3}}},{{{2}}})

*[invoke calculating_slope 6, -2, -3, 2]


11.) find the equation of a line that passes thru the points ({{{-11}}},{{{-4}}}) and ({{{9}}},{{{8}}})

*[invoke calculating_slope -11, -4, 9, 8]



since you can't see the points on a graph above, I will do it again:


{{{drawing( 600, 600, -15, 15, -15, 15,
circle(-11,-4,.2), circle(9,8,.2),locate(-11,-4,p(-11,-4)), locate(9,8,p(9,8)), 
graph( 600, 600, -15, 15, -15, 15, (3/5)x+13/5)) }}}



12.) Rewrite the equation {{{y=3x-7}}} in function notation and find {{{f(8)}}}

{{{f(x)=3x-7}}} 

{{{f(8)=3*8-7}}} 

{{{f(8)=24-7}}}

{{{f(8)=17}}}
  

13.) Determine whether the graphs of {{{2x+3y=6}}} and {{{6y=-4x+7}}} are parallel, perpendicular, or neither.

parallel lines have same slope
perpendicular lines have slopes negative reciprocal to each other

let's find the slopes; write both equations in slope-intercept form {{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} is y-intercept

{{{2x+3y=6}}} 
{{{6y=-4x+7}}}
-----------------

{{{3y=-2x+6}}} 
{{{6y=-4x+7}}}
---------------

{{{y=-(2/3)x+2}}} 
{{{y=-(cross(4)2/cross(6)3)x+7/6}}}
--------------------

{{{y=highlight(-(2/3))x+2}}} 
{{{y=highlight(-(2/3))x+7/6}}}
--------------------

as you can see, both lines have same slope which means they are {{{parallel}}} lines

see them on a graph:

{{{ graph( 600, 600, -10, 10, -10, 10, -(2/3)x+2, -(2/3)x+7/6) }}}