Question 941844
A woman is 6 times older than her child.The product of their ages 7 years ago was 180.Find their present age 
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w = woman's age now
c = child's age now
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w = 7c
(w - 7)*(c - 7) = 180
(7c - 7)*(c - 7) = 180
{{{7c^2 - 56c + 49 = 180}}}
{{{7c^2 - 56c - 131 = 0}}}
*[invoke solve_quadratic_equation 7,-56,-131]
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c = 9.892 years
w = 69.244 years
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It's not an integral solution, probably because the moron that wrote the problem thinks "6 times older" is the same as 6 times as old.
6 times older = 7 times as old.
1 time older = 2x, not the same age.