Question 941776
Two consecutive even integers, I and I+2
Product is 168, (I)(I+2)=168
{{{I^2+2I=168}}} Subtract 168 from each side
{{{I^2+2I-168=0}}}*[invoke quadratic "I", 1, 2, -168 ]
The results are 12 and -14. The integer specified is positive, so I=12 and the second is I+2=14
CHECK:the product of 12 and 14 is (12)(14}=168
The ANSWER (SOLUTION) Is 12 and 14