Question 941694
The length of the frame is three times the width and it's diagonal measurement is 160 cm, what are the dimensions of the frame?
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let x=width of rectanglar frame
3x=length of rectangular frame
By the pythagorean theorem:
√(width^2+length^2)=diagonol
√((x^2)+(3x)^2)=√x^2+9x^2=√(10x^2)=160
√(10x^2)=160
√10x=160
x=160/√10≈50.60
3x=3*160/√10≈151.79
width of rectanglar frame≈50.60 cm
length of rectangular frame≈151.79 cm