Question 941676
(A) {{{y = (0.2)^x}}}	
(B) {{{y = 2^x}}}
(C) {{{y = (1/3)^x }}} 
(D) {{{y = 4^x}}}

if {{{x=0}}} all given functions will be {{{1}}}; so, all of them have same y-intercept and it is {{{1}}}

since 
(A) {{{y = (0.2)^x}}} =>{{{y = (2/10)^x}}} =>{{{y = (1/5)^x}}}=>{{{y = 5^(-x)}}},  have graph at II quadrant
and (C) {{{y = (1/3)^x }}} =>{{{y = (1/3)^x}}}=>{{{y = 3^(-x)}}}, they have graph at II quadrant

so, A and C could be only {{{f}}} and {{{g}}}

since {{{f}}} is closer to {{{y-axis}}} then {{{g}}}, means it growth is "bigger" and "faster" then {{{g}}}; so, we can say

{{{highlight(f)}}} is  {{{highlight(y=(1/3)^x)}}} then

{{{highlight(g)}}} is {{{highlight(y = (0.2)^x)}}} 

in I quadrant we have B and D, evidently D  is growing "bigger" and "faster" then B, so

{{{highlight(n)}}} is {{{highlight(y=2^x)}}}

{{{highlight(m) }}}is {{{highlight(y=4^x)}}}