Question 1755
to answer you, I will have to assume that you understand straight line graphs and you can sketch them from "y=mx+c"...I am English, and i assume you are American so i hope you know what i mean by y=mx + c. If not, we are stuck.

Anyway..inequalities are very easy...no sweat. Treat them just like normal equations. The ONLY difference is when you have to multiply or divide by a negative number...THEN the inequality sign changes round.

so, number 1:

let us do 2 equations. First r+7=-5

1. move the 7 to the other side, gives r = -12. Done!

Now, lets do, r+7>-5

1. move the 7 to the other side, gives r > -12. Done!

Easy :-)

OK, second equation is -35+6n < 7n

First, move the 6n to the other side (by subtracting 6n). So, we then have -35 < n. The n (or more formally 1n) came from 7n - 6n

So this is the answer....n > -35...all i have done is write the whole of "-35 < n" the other way round...no maths.

I shall leave you with 3 and 4.

As for verifying...draw a graph of y=-12 (or r=-12, whatever). This line is where y (or r) EQUALS -12. You want everywhere where y (or r) is GREATER than -12... so shade everywhere where that is true.

Similarly, for number 2, draw the graph (straight line) of n=-35. Then shade the region of the graph where n is GREATER than -35...


Hope this helps
Jon