Question 80039
ok here is the quadratic formula
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}

now a=5 b=-3 c=2

just subsitute the numbers in the formula
{{{x = (3 +- sqrt( 9-4*5*2 ))/(2*5) = (3 +- sqrt(-31))/(10)}}}

i'm not sure if you learned imaginary numbers by now, but if so then the answer becomes 
{{{(3 +- sqrt(31)i)/(10)}}}