Question 941551
If it takes 3men 56hours to dig a hole 4mX6mX5m, and two of the men work twice
as fast as the third,find the number of hours that will take the two faster men to dig this hole together.
let x=amt of work slower man can do in one hr
his work rate=1/x
2/x=work rate of each faster man
{{{56*1/x+56*2/x+56*2/x=1}}}
280/x=1
x=280
..
2x/280+2x/280=1
4x/280=1
4x=280
x=70 hrs