Question 941497
{{{g(x) =(x+7)/(x^2-8x+15)}}}
    denominator  = x^2-8x+15
 on factorizing the  denominator
 {{{x^2-8x+15 = x^2-3x-5x+15}}}
 ={{{x(x-3)-5(x-3)}}}
 ={{{(x-3)(x-5)}}}
the above expression becomes 0 , when x= either 3 or 5
for the function to exist, denominator should not be 0
 hence domain is all real number  expect 3 & 5
Result : Domain = R-{3,5}  
 R= all near numbers set